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.10x^2+6.66x-200=0
a = .10; b = 6.66; c = -200;
Δ = b2-4ac
Δ = 6.662-4·.10·(-200)
Δ = 124.3556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.66)-\sqrt{124.3556}}{2*.10}=\frac{-6.66-\sqrt{124.3556}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.66)+\sqrt{124.3556}}{2*.10}=\frac{-6.66+\sqrt{124.3556}}{0.2} $
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